GATE Aptitude Questions with Answers - Download PDF

The GATE aptitude questions comprise all the essential topics, including problems on train and time, distance height and distance time, and work, simple interest, compound interest, profit and loss, partnership, percentage problems on ages, calendar, clock, average, area, volume and permutation and combination.

All these topics are an essential part of the GATE exam 2026, and candidates should practise them carefully to assess their readiness for the exam.

Those aiming to enhance their time management skills and complete the exam within the allotted time can benefit significantly from the GATE question paper.

The GATE Aptitude questions with answers likely to be asked in GATE 2026 are added in the PDF below, and students can download the PDF directly by clicking on the link.

Top 10 GATE Aptitude Questions with Answers

The top 10 GATE aptitude questions with answers are added below, comprising all the essential topics such as problems on train and time,  distance height and distance time, work, simple interest, compound interest, profit and loss. Students are advised to solve them to understand and grasp their subjects.

Question 1. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

1. 3.6
2. 7.2
3. 8.4
4. 10

Ans. Option B

Speed =600/5 x 60 m/sec.

 = 2 m/sec.

Converting m/sec to km/hr (see essential formulas section)

=2 x18/5km/hr

= 7.2 km/hr

Also Check: GATE Answer Key 2026

Question 2. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual Distance travelled by him is:

1. 50 km
2. 56 km
3. 70 km
4. 80 km

Ans. Option A

Let the actual Distance travelled be x km.

Then, x = x + 20

=X/10 X+20/14

= 14x = 10x + 200

= 4x = 200

= x = 50 km.

Also Check: GATE Exam Dress Code 2026

Question 3. A train can travel 50% faster than a car. Both start from point A and reach point B 75 km away from A simultaneously. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

1. 100 kmph
2. 110 kmph
3. 120 kmph
4. 130 kmph

Ans. Option C

Let time be t.

Suppose the car is going at speed x,

Train speed will be x+(x/2) = 3x/2 = 1

Speed of Train(dist/time) = 75/(t-12.5) = 2

1 =2.

3x/2 = 75/t =3

Speed of car = 75/t.

x = 75/t = 4.

substitute 4 in 3.

By solving, you get;

time of car(t) = 37.5(in min)

By converting into hr.

t = 0.625 hr.

Speed of car = 75/0.625.

Ans: 120 kmph

Question 4. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr, and the flight time increased by 30 minutes. The duration of the flight is:

1. 1 hour
2. 2 hours
3. 3 hours
4. 4 hours

Ans. Option A

See, we know D = ST.

Now,

d = 600 km.

Let,

Old speed = x km/hr <- taken time by T hr.

Original speed = (x-200)Km/hr <- taken time 3T/2.

(3T/2= T + extra 30 mins )=(1+30/60)T).

So,

600 = xT & 600 = (x-200)3T/2 = (3xT/2) - 300T

Now 300T = 900 - 600.

Finally, T = 1hr.

Also Read: GATE 2026 Preparation Tips from Toppers & Experts

Question 5. A man completes a journey in 10 hours. He travels the first half of the journey at the rate of 21 km/hr and the second half at the rate of 24 km/hr. Find the total journey in km.

1. 220 km
2. 224 km
3. 230 km
4. 234 km

Ans. Option B

=X/21 + X/24 = 10,

=15X/168 = 10,

=X = 112,

=2X = 224.

Question 6. A man on tour travels 160 km at 64 km/hr and 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

1. 35.55 km/hr
2. 36 km/hr
3. 71.11 km/hr
4. 71 km/hr

Ans. Option C

Total distançe = 160+160=320

Total time = 160/64+160/80 = 4.5 = 9/2.

Av speed = TD/TT.

= 320/9/2.

= 71.11km/h.

Also Read: GATE Negative Marking 2026

Question 7. In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, he will take 1 hour less than Sameer. Abhay's speed is:

1. Five kmph
2. 6 km
3. 6.25 km
4. 7.5 km

Ans.  Option A

=Take the ratio of the speed of Abhay: 1:2

=Then, we get the time ratio for the inverse time, so it is 2:1.

=The Gap is 1 unit, which is given as the sum of 3 hours.

=So 2=6 hours and 1= 3 hours.

=So we get the ans by applying a formula that is S= D/T

=S= 30/6, which is equal to 5.

Question 8. Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. If he travels at 10 mph, he will reach there at 12 noon if he travels at 15 mph. At what speed must he travel to reach A at 1 P.M.?

1. 8 kmph
2. 11 kmph
3. 12 kmph
4. 14 kmph

Ans. Option C

Case1: speed = 10kmph.

Ce2: speed = 15kmph.

Given d/10-d/15 = 2,

d=60,

case1 time=60/10, time=6,

case2 time=60/15, time=4,

so, at noon, time is 4, and at 2 pm, it is 6

Moreover, 1 pm is between them so that it will be 5.

And 60/5=12.

Question 9. It takes eight hours for a 600 km journey if 120 km is done by train and the rest by car. It takes 20 minutes more if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:

1. 2 : 3
2. 3: 2
3. 3: 4
4. 4 : 3

Ans. Option C

We got that,

Eq 1: 1/x+4/y=1/15 =1/x=1/15-4/y.

Eq 2: 1/x+2/y=1/24 =1/x=1/24-2/y.

Now equate the 1/x values.

i.e 1/15-4/y = 1/24-2/y =2/y = 1/15-1/24.

=So you get y = 80.

=By submitting y in the eq 1: 1/x+4/80=1/15 and you get x =60.

=X : Y = 60:80 =3:4.

Question 10. A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot at the rate of 4 km/hr and partly on bicycle at the rate of 9 km/hr. The Distance travelled on foot is:

14 km

15 km

16 km

17 km

Ans. Option C

Farmer travels - 4 km/hr.

Speed = 4km/hr and Time = 4 hours.

Well, in 1 hour, he travels 1 Km, then in 4 hours, he will travel 4km.

So, Distance = Speed * Time.

= 4km/hr * 4hr.

= 16km (HR gets cancelled).