The minimum rank required in JEE Main 2025 for NIT Surathkal is 1528 for CSE, 10057 for Mechanical Engineering and 5728 for Electrical Engineering. The cutoff is released during the JoSAA counselling 2025.
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The minimum rank required in JEE Main 2025 is 1528 for CSE, 10057 for Mechanical Engineering and 5728 for Electrical Engineering, as per the JoSAA cutoff 2025 round 1. However, the cutoff is likely to differ based on your categories, ranks, preferences, number of applicants and other such factors.
The JEE Main cutoff 2025 for NIT Surathkal is released in the form of opening and closing ranks on the official website of JoSAA. It is advisable to keep a check on the cutoff for all rounds to anticipate your chances of admission to the institute.
Minimum Rank in JEE Main 2025 Required for NIT Surathkal
The JoSAA seat allocation 2025 is based on the rank acquired by you, along with other factors, including your preferences, categories, seat availability, number of applicants and more. Thus, it may be difficult to check whether you can gain admission to your desired college, even before the release of the seat allotment result.
However, you need not worry more! You can have a look at the minimum rank required in JEE Main 2025 for NIT Surathkal. This way, you will be able to analyse your chances of admission to the institute. The category-wise JEE Main cutoff 2025 is provided in the table below for round 1:
Minimum JEE Main 2025 Rank Required by the Open Category for NIT Surathkal
Find the JEE Main 2025 opening and closing ranks required to be obtained by the open category for NIT Surathkal from the table below:
Academic Program Name |
Quota |
Opening Rank |
Closing Rank |
Artificial Intelligence (4 Years, Bachelor of Technology) |
HS |
2815 |
3438 |
Artificial Intelligence (4 Years, Bachelor of Technology) |
OS |
1607 |
2372 |
Civil Engineering (4 Years, Bachelor of Technology) |
HS |
11984 |
22534 |
Civil Engineering (4 Years, Bachelor of Technology) |
OS |
5148 |
19255 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
HS |
1050 |
2726 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
OS |
753 |
1528 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
HS |
5870 |
6674 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
OS |
3407 |
5728 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
HS |
3415 |
5327 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
OS |
2019 |
3934 |
Information Technology (4 Years, Bachelor of Technology) |
HS |
3025 |
4086 |
Information Technology (4 Years, Bachelor of Technology) |
OS |
1540 |
2787 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
HS |
3588 |
11166 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
OS |
6485 |
10057 |
Also Read: What is the Minimum JEE Main Rank 2025 Required for NIT Calicut?
Minimum JEE Main 2025 Rank Required by SC for NIT Surathkal
Find the JEE Main opening and closing ranks required to be obtained by the SC category for NIT Surathkal from the table below:
Academic Program Name |
Quota |
Opening Rank |
Closing Rank |
Artificial Intelligence (4 Years, Bachelor of Technology) |
HS |
780 |
909 |
Artificial Intelligence (4 Years, Bachelor of Technology) |
OS |
441 |
453 |
Civil Engineering (4 Years, Bachelor of Technology) |
HS |
1976 |
3719 |
Civil Engineering (4 Years, Bachelor of Technology) |
OS |
1813 |
3123 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
HS |
220 |
731 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
OS |
210 |
322 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
HS |
2040 |
2326 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
OS |
867 |
1207 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
HS |
804 |
1551 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
OS |
621 |
808 |
Information Technology (4 Years, Bachelor of Technology) |
HS |
917 |
1417 |
Information Technology (4 Years, Bachelor of Technology) |
OS |
452 |
571 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
HS |
1078 |
3065 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
OS |
1194 |
2175 |
Minimum JEE Main 2025 Rank Required by ST for NIT Surathkal
Find the JEE Main opening and closing ranks required to be obtained by the ST category for NIT Surathkal from the table below:
Academic Program Name |
Quota |
Opening Rank |
Closing Rank |
Artificial Intelligence (4 Years, Bachelor of Technology) |
HS |
474 |
474 |
Artificial Intelligence (4 Years, Bachelor of Technology) |
OS |
138 |
138 |
Civil Engineering (4 Years, Bachelor of Technology) |
HS |
1032 |
1778 |
Civil Engineering (4 Years, Bachelor of Technology) |
OS |
407 |
743 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
HS |
159 |
354 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
OS |
101 |
124 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
HS |
532 |
782 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
HS |
922 |
922 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
OS |
479 |
597 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
HS |
434 |
478 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
OS |
237 |
459 |
Information Technology (4 Years, Bachelor of Technology) |
HS |
481 |
500 |
Information Technology (4 Years, Bachelor of Technology) |
OS |
292 |
292 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
HS |
971 |
1312 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
OS |
444 |
838 |
Also Read: Minimum Rank Required in JEE Main for NIT Jamshedpur Admission 2025
Minimum JEE Main 2025 Rank Required by OCB NCL for NIT Surathkal
Find the JEE Main opening and closing ranks required to be obtained by the OCB NCL category for NIT Surathkal from the table below:
Academic Program Name |
Quota |
Opening Rank |
Closing Rank |
Artificial Intelligence (4 Years, Bachelor of Technology) |
HS |
1301 |
2274 |
Artificial Intelligence (4 Years, Bachelor of Technology) |
OS |
540 |
723 |
Artificial Intelligence (4 Years, Bachelor of Technology) |
OS |
1792 |
1792 |
Civil Engineering (4 Years, Bachelor of Technology) |
HS |
6742 |
8757 |
Civil Engineering (4 Years, Bachelor of Technology) |
OS |
5623 |
6463 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
HS |
638 |
1761 |
Computer Science and Engineering (4 Years, Bachelor of Technology) |
OS |
342 |
495 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
HS |
3627 |
4210 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
OS |
2122 |
2372 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
HS |
2491 |
3623 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
OS |
1240 |
1687 |
Information Technology (4 Years, Bachelor of Technology) |
HS |
1999 |
3057 |
Information Technology (4 Years, Bachelor of Technology) |
OS |
735 |
1142 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
HS |
4401 |
6091 |
Mechanical Engineering (4 Years, Bachelor of Technology) |
OS |
3111 |
4022 |
Course-wise Minimum Rank Required in JEE Main 2025 for NIT Surathkal
The minimum rank required in JEE Main 2025 for NIT Surathkal also varies across courses. Usually, the popular courses like CSE and ME have high cutoffs. Here's a quick overview of the same:
Academic Program Name |
Seat Type |
Opening Rank |
Closing Rank |
Artificial Intelligence (4 Years, Bachelor of Technology) |
OPEN |
1607 |
2372 |
EWS |
269 |
309 |
|
OBC-NCL |
540 |
723 |
|
SC |
441 |
453 |
|
ST |
138 |
138 |
|
Civil Engineering (4 Years, Bachelor of Technology) |
OPEN |
5148 |
19255 |
EWS |
2755 |
2810 |
|
OBC-NCL |
5623 |
6463 |
|
SC |
1813 |
3123 |
|
ST |
407 |
743 |
|
Computer Science and Engineering (4 Years, Bachelor of Technology) |
OPEN |
753 |
1528 |
EWS |
173 |
287 |
|
OBC-NCL |
342 |
495 |
|
SC |
210 |
322 |
|
ST |
101 |
124 |
|
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) |
OPEN |
3407 |
5728 |
EWS |
990 |
1158 |
|
OBC-NCL |
2122 |
2372 |
|
SC |
867 |
1207 |
|
ST |
479 |
597 |
|
Electronics and Communication Engineering (4 Years, Bachelor of Technology) |
OPEN |
2019 |
3934 |
EWS |
450 |
599 |
|
OBC-NCL |
1240 |
1687 |
|
SC |
621 |
808 |
|
ST |
237 |
459 |
|
Information Technology (4 Years, Bachelor of Technology) |
OPEN |
1540 |
2787 |
EWS |
295 |
372 |
|
OBC-NCL |
735 |
1142 |
|
SC |
452 |
571 |
|
ST |
292 |
292 |
|
Mechanical Engineering (4 Years, Bachelor of Technology) |
OPEN |
6485 |
10057 |
EWS |
1438 |
1949 |
|
OBC-NCL |
3111 |
4022 |
|
SC |
1194 |
2175 |
|
ST |
444 |
838 |
Also Read: How Many Marks are Required in JEE Main 2025 for NIT Silchar Admission?
NIT Surathkal Admission Process Through JEE Main 2025
Willing to gain admission to NIT Surathkal? The admission to the institute is based on the JoSAA counselling 2025. You can follow the steps mentioned below:
Registration and Choice Filling:
Candidates who have qualified in JEE Main need to register on the JoSAA (Joint Seat Allocation Authority) official website and fill in their preferred choices of institutes and branches. This step is crucial as seat allocation is based on these choices.
Mock Seat Allocation:
JoSAA conducts mock seat allocation rounds to help candidates understand their chances of getting a seat based on their choices and rank.
Seat Allotment:
Based on JEE Main scores and the choices made during the JoSAA choice filling process, you will be allotted seats across multiple rounds.
Seat Acceptance and Document Verification:
Candidates who are allotted seats need to accept the seat and complete online document verification and fee payment within the specified timelines.
Final Admission:
Once the documents are verified and fees are paid, the seat is provisionally confirmed. Final admission is subject to successful verification of certificates, joining the allotted institute, and payment of any remaining fees.
CSAB Counselling:
After JoSAA rounds, the Central Seat Allocation Board (CSAB) conducts special rounds to fill any vacant seats in NITs, IIITs, and GFTIs.
How is the Campus Life at NIT Surathkal?
You might be doubtful whether admission to NIT Surathkal through JEE Main 2025 is worth it or not. Here's what you need to know about the campus life at the institute:
- Academic Infrastructure:
- Well-equipped labs and research centres for advanced learning.
- Highly qualified faculty from IITs, NITs, and leading universities.
- Student Activities and Clubs:
- Technical clubs- Robotics, Coding, AI, Data Science.
- Incident (Cultural Fest) and Engineer (Technical Fest).
- Sports facility: Gym, swimming pool, and various sports teams.
- Placements and career opportunities:
- Top Recruiters: Google, Microsoft, Amazon, Flipkart, and Tata Motors.
- Highest Package: INR 50+ LPA.
- Average package: 12-18 Lakhs LPA for CSE/ECE, and INR 7 LPA - INR 10 LPA for other branches.
Also Read: Minimum Marks Required in JEE Main 2025 for NIT Delhi Admission
NIT Surathkal continues to be one of the most sought-after NITs in India. If you are aspiring to get admission into this institution, it is essential to understand the minimum JEE Main rank required based on your preferred branch, category, and state quota. The minimum rank required for NIT Surathkal in JEE Main 2025 is around 1500- 3000 for the general category, below 1700 for the OBC category, below 700 for the SC category, below 300 for the ST category, and below 400 for the EWS and PWD category. With proper preparation, strategic choice filling, and timely counselling participation, you can significantly increase your chances of securing a seat at NITK Surathkal.
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