What is the oxidation state of Fe in [Fe(H2O)5(NO)] SO4?

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Answered By: GetmyuniEnterprise | May 27, 2024 5:51:10 PM

The oxidation state of sulfate (SO4) is -2. Each water molecule (H2O) has an oxidation state of 0 (hydrogen +1, oxygen -2). The nitroso ion (NO) has an oxidation state of +1 (nitrogen +2, oxygen -2). To get a neutral charge in the entire complex molecule, the sum of the oxidation states of all it's components must equal zero. Therefore: x (Fe) + 5(0) + 1(NO) - 2(SO4) = 0 x (Fe) + 1 - 2 = 0 x (Fe) = +1 Therefore, the oxidation state of iron (Fe) in [Fe(H2O)5(NO)]SO4 is +1.

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