The candidates are required to visit the official college website of Silicon Institute of Technology in order to complete the admission application process.
The candidates have to click on the application procedure option to start application process.
The candidates are required to fill in all the necessary details that have been asked in order to complete the admission register process.
The candidate should check the details that he/she have put in before submitting the admission application form.
Step 1: The candidates have to go through the following website to apply online.
Step 2: The candidates have to click on the admission procedure to get application form and start filling the correct details as follows.
Step 3: The confirmed notification will be shown on the screen and candidates will be instructed for further steps in application.
For B.Tech, seats will be alloted on the basis of merit in JEE and OJEE for College website, admission 2019.
The admission for PG courses will be done through counselling based on the scores of PGAT / GATE.
Final allotment letter of OJEE,
Photo copy of JEE Rank Card,
Document verification Slip of OJEE,
OJEE Fees payment receipt copy of Rs. 10,000/‐,
10th Mark Sheet,
12th Mark Sheet,
B.Sc / B.C.A./ Diploma certificate,
B.Sc / B.C.A./ Diploma Mark sheet,
Original School / College Leaving / Transfer Certificate,
Original Character / Conduct Certificate of last institute (School / College),
Blood Group Certificate (Original),
3 colour Passport size photographs,
Photo copy of ID proof / Address proof / Aadhaar Card.
For admission in SIT, Bhubaneswar for 2019, candidates should have passed (10+2) or Equivalent with Physics, Mathematics, Chemistry/Biotechnology, Language and any other subject with minimum of 45% marks.
Reserved category students have a 5% relaxation in minimum aggregate.
For admission into 1st year B.Tech programme a student has to appear for Joint Entrance Examination (JEE) conducted by CBSE, New Delhi.
For admission into 2nd Year B. Tech. (Lateral Entry), student has to appear for Orissa Joint Entrance Examination (OJEE).
For admission in SIT, Bhubaneswar, candidates should have passed graduation or an equivalent from a recognised institution.
Admission to courses are done through central counseling based on OJEE scores.
The candidates should have a bachelor's degree in Science or Engineering discipline obtained through the 10+2+4 system or an equivalent qualification with a minimum aggregate of 55% or equivalent CGPA of any of the Universities incorporated by an act of the central or state legislature in India for SIT, Bhubaneswar, admission 2019.
A Relaxation of 5% aggregate for admission is there for SC/ST candidates.
Candidate has to go through central counseling based on PGAT and GATE 2019 scores.
Eligibility criteria that you have already passed 12th with science background in PCM and admission process is through jee main Or ojee. I took admission through jee main. In my year cutoffs rank are -: For outside state 1. Comp. Science engg.- (100k) 2. Electronics and communication engg.- (250k) 3. Electrical and eletronics engg. -(300k) 4. Applied electronics and instruments engg. - (400k) For home state 1. Comp. Science engg.- (200k) 2. Electronics and communication engg.- (350k) 3. Electrical and eletronics engg. -(500k) 4. Applied electronics and instruments engg. - (600k)
Eligibility criteria- A student must complete his/her 12th in science stream with an average mark Entertainment exam- Get a good mark or rank in all India Jee main exam and after that your rank will evaluate through OJEE and admission take place in month of July Cutoffs- the cutoff is not much high but it should be average one because silicon is counted the best college in BPUT university.
Edibility criteria :- A student must have passed 12th board exams with 70% of aggregate marks from CBSE or state boards Admission in this college are done by the OJEE counselling, on the basis of JEE MAIN rank . In 2017 the students who got 80+ in JEE MAIN was able to get computer science branch.fOdishasha domicile candidates cutoffs are low a bit
The eligibility criteria for Silicon Institute of Technology differs from branch to branch, but it basically depends on the rank of the applicant in JEE Mains. Usually, Computer Science branch has higher cut-offs then EEE, ECE, AEI. For CS the branch cut off goes around 1,50,000 to 2,75,000. Rest for all other branches any rank within 4,50,000 will do.
Being one of best colleges of Odisha, SIT takes students based on your JEE rank. You have to apply OJEE 2018 college selection. CSE being the top branch you have to get a rank of 1 lakh 50 thousand to get it. But there are other branches such as ETC, EEE, AEI. There are very good facilities in our college which makes your foundation strong.